I need some help with a math problem I am no good at math. If a rear end ratio is 3.78:1 and an overdrive is added, which is a 26% overdrive, what is the final ratio in overdrive? And how do you do that????
Math problem
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Bill,
You may to read the following article.
http://books.google.com/books?id=3AJxi5DzoBcC&pg=PT900&lpg=PT900&dq=calculate+final+overdrive+output+ration&source=bl&ots=DGXw6_c2ip&sig=un8xc5tTD77J2epvbCkFTVwYAxk&hl=en&ei=GaDvSvn6GMKWtgfAvMn5Bw&sa=X&oi=book_result&ct=result&resnum=6&ved=0CCEQ6AEwBQ#v=onepage&q=&f=false
This explains in detail the calculations and the information you need to make the calculations.
Robert
there are 7 girls on a bus, no driver, each girl has 7 backpacks, there are 7 large cats in each backpack,
for each large cat there are 7 small cats, how many legs are on the bus?
Thats a 5th grade math problem.
Yours is a bit easier. :eyeroll:
RS
I'll bet one of the cats is an amputee just to mess with us.
Thanks for the replies. It is just morning, and already my head hurts. I have a vision in my head of a four legged bus walking down the road full of girls and cats.
none, busses don't have legs"
Not a trick question! One of those 5th grader problems.
Doglegs dont count either (if a bus has those :S)
RS
BTW Bill, I hope your question was answered B)
Joe got this one right on the first try.
3.78 times 0.26=.982 This is the amount that the final drive is going to be reduced.( Can be read as 26% of 3.78 is 0.982)
So, if you started with a 3.78 ratio, simply subtract the 0.982 from the 3.78 and you get the answer: 2.798. Round up to 2.8 if you wish.
Someone building a salt flats car?
Pete
there are 7 girls on a bus, no driver, each girl has 7 backpacks, there are 7 large cats in each backpack,
for each large cat there are 7 small cats, how many legs are on the bus?
Thats a 5th grade math problem.
Yours is a bit easier. :eyeroll:
RS"
There are 10,990 legs on the bus. :eyepop:
Joe got this one right on the first try.
3.78 times 0.26=.982 This is the amount that the final drive is going to be reduced.( Can be read as 26% of 3.78 is 0.982)
So, if you started with a 3.78 ratio, simply subtract the 0.982 from the 3.78 and you get the answer: 2.798. Round up to 2.8 if you wish.
Someone building a salt flats car?
Pete"
No salt flats. The model A ford ( I have several) comes stock with 3.78:1. Mitchell makes a 26% overdrive. I have 3.54:1 in two of my cars, but was considering a 3.27:1 for the roadster pickup, and wanted to see how it would compare to the overdrive. It seems like it would work fine.
Sorry it was not an mg question, but I suspected the math problem would be better solved here, than on a Model A forum.
A bus full of pussys?"
Yes, for sure. Mrs. Slocum comes to mind.
[quote=NOHOME]
Joe got this one right on the first try.
3.78 times 0.26=.982 This is the amount that the final drive is going to be reduced.( Can be read as 26% of 3.78 is 0.982)
So, if you started with a 3.78 ratio, simply subtract the 0.982 from the 3.78 and you get the answer: 2.798. Round up to 2.8 if you wish.
Someone building a salt flats car?
Pete"
No salt flats. The model A ford ( I have several) comes stock with 3.78:1. Mitchell makes a 26% overdrive. I have 3.54:1 in two of my cars, but was considering a 3.27:1 for the roadster pickup, and wanted to see how it would compare to the overdrive. It seems like it would work fine.
Sorry it was not an mg question, but I suspected the math problem would be better solved here, than on a Model A forum.[/quote]
Are you implying that the model A boys ain't as smarts as the boys here.
[quote=rrmgb]
there are 7 girls on a bus, no driver, each girl has 7 backpacks, there are 7 large cats in each backpack,
for each large cat there are 7 small cats, how many legs are on the bus?
Thats a 5th grade math problem.
Yours is a bit easier. :eyeroll:
RS"
There are 10,990 legs on the bus. :eyepop:[/quote]
You missed the legs on the cat's fleas.
I have my shoes off and I still can’t figure it out?"
Here's the solution...
Each backpack holds 56 cats
7 x 7 = 49
49 + 7 =56
56 cats x 7 backpacks = 392 cats
392 cats x 7 girls = 2744
2744 cats x 4 legs each = 10,976
10,976 legs + 14 legs(7 girls) = 10,990
:eyepop: :eyepop: :eyepop: :eyepop:
[quote=2manycars]
[quote=NOHOME]
Joe got this one right on the first try.
3.78 times 0.26=.982 This is the amount that the final drive is going to be reduced.( Can be read as 26% of 3.78 is 0.982)
So, if you started with a 3.78 ratio, simply subtract the 0.982 from the 3.78 and you get the answer: 2.798. Round up to 2.8 if you wish.
Someone building a salt flats car?
Pete"
No salt flats. The model A ford ( I have several) comes stock with 3.78:1. Mitchell makes a 26% overdrive. I have 3.54:1 in two of my cars, but was considering a 3.27:1 for the roadster pickup, and wanted to see how it would compare to the overdrive. It seems like it would work fine.
Sorry it was not an mg question, but I suspected the math problem would be better solved here, than on a Model A forum.[/quote]
Are you implying that the model A boys ain't as smarts as the boys here.[/quote]
Right. And there would likely be more arguing over the results.
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